(x^2 y^2-1)^3=x^2y^3 226248-(x^2+y^2-1)^3-x^2y^3=0 wolfram alpha
Solving Equations Exactly ¶ The solve function solves equations To use it, first specify some variables;マーキー 生き残ります 換気 X 2 Y 2 1 3 X 2y 3 0 Gaia Co Com For more information and source, see on this link http//wwwgaiacocom/x2y213x2y301 Answer1 Active Oldest Votes 3 The solution set is obviously symmetric with respect to the y axis Therefore we may assume x ≥ 0 In the domain { ( x, y) ∈ R 2 x ≥ 0 } the equation is equivalent with x 2 y 2 − 1 = x 2 / 3 y , which can easily be solved for y y = 1 2 ( x 2 / 3 ± x 4 / 3 4 ( 1 − x 2 Solutions To Implicit Differentiation Problems (x^2+y^2-1)^3-x^2y^3=0 wolfram alpha
